Four equal masses of 4.0 kg are placed at the vertices of a square of side 8.0 m. Find the force on the mass at the top left vertex.
4 answers
Doesn't make sense. Why would putting mass on the corners of a square cause a force on one of the masses?
Force of gravity?
(a) Given that the energy released per fission of 235U nucleus is 200MeV, calculate (i) the number of fissions and (ii) the amount of energy (in joules) available if 50g of 235U is completely fissioned.
Fx = +G m m /8^2 + G m m /(8sqrt2)^2 = G m^2 [1/64 + 1/128]
Fy =-G m^2[ 1/64 +1/128]
Fy =-G m^2[ 1/64 +1/128]
0 answers