Four different towns in the same state grew in size due to a renewal effort. The population of town A grew from 22,000 to 24,500 in 4 years. The population of town B grew from 31,200 to 34,770 in 6 years. The population of town C grew from 18,000 to 22,000 in 5 years. The population of town D grew from 32,000 to 34,100 in 3 years.

Which town had the greatest average change in population over the corresponding time period? (1 point)
© town B
C town c
O town D
C) town A

1 answer

To determine which town had the greatest average change in population over the corresponding time period, we need to calculate the average change in population for each town.

For town A:
Initial population = 22,000
Final population = 24,500
Time period = 4 years

Average change = (Final population - Initial population) / Time period
= (24,500 - 22,000) / 4
= 2,500 / 4
= 625

For town B:
Initial population = 31,200
Final population = 34,770
Time period = 6 years

Average change = (Final population - Initial population) / Time period
= (34,770 - 31,200) / 6
= 3,570 / 6
= 595

For town C:
Initial population = 18,000
Final population = 22,000
Time period = 5 years

Average change = (Final population - Initial population) / Time period
= (22,000 - 18,000) / 5
= 4,000 / 5
= 800

For town D:
Initial population = 32,000
Final population = 34,100
Time period = 3 years

Average change = (Final population - Initial population) / Time period
= (34,100 - 32,000) / 3
= 2,100 / 3
= 700

Comparing the average changes in population for each town, we can see that town C had the greatest average change in population over the corresponding time period. So the correct answer is C) town C.