To find the equation connecting p and q, we can use the given points (q=80, p=12) and (q=300, p=50) to solve for the constants K and C in the linear relation p=KQ+C.
From the first point:
12 = K(80) + C
12 = 80K + C (1)
From the second point:
50 = K(300) + C
50 = 300K + C (2)
Subtracting equation (1) from equation (2) gives:
50 - 12 = 300K - 80K + C - C
38 = 220K
K = 38/220
K = 0.1727
Substitute K back into equation (1) to solve for C:
12 = 80(0.1727) + C
12 = 13.816 + C
C = 12 - 13.816
C = -1.816
Therefore, the equation connecting p and q is: p = 0.1727q - 1.816
Formular
V=a+bu
Question
Two quantities p and q are connected by a linear relation of the form p=KQ+C where c and k are constant, if q =80, when p=12, and q =300 and p=50
A. Find the equation connecting p and q
1 answer
1 answer