Form the smallest 6 digit even number using the number 4 0 9 3 8 and 7

Answer 1

To form the smallest 6-digit even number using the digits 4, 0, 9, 3, 8, and 7, we must consider the following aspects:

1. The number must contain all six digits.
2. To make it the smallest possible number, the digits must be arranged in ascending order (from smallest to largest).
3. To ensure the number is even, it must end with an even digit.

Given the digits, the even digits are 0, 4, and 8. Of these, 0 cannot be used at the end of the number because it wouldn't change the value of the 5-digit number to a 6-digit number. So, we're left with 4 and 8 as possible ending digits.

If we try to put 4 at the end to make it even, the number could start with 0, which is not desirable for a 6-digit number. So, we should use 8 at the end and 0 as the second smallest number.

Arranging the digits in ascending order while keeping these constraints in mind, we get:

- The first digit should be the smallest non-zero digit, which is 3.
- The second digit should be the next smallest, which is 0.
- The next smallest digits are 4 and 7.
- The next smallest digit remaining is 9.

Putting it all together, we have 30479, but we still need an "even" digit at the end to satisfy all constraints. The smallest even digit to use that we haven't used yet is 8.

So, the smallest 6-digit even number you can form with the digits 4, 0, 9, 3, 8, and 7 is 304798.