Let's consider two cases:
Case 1: Forces F1 and F2 are applied in the same rotational direction.
In this case, the net torque will be the sum of the individual torques due to F1 and F2.
Torque1 = F1 x radius = 7.50 N x 0.330 m = 2.475 Nm
Torque2 = F2 x radius = 5.30 N x 0.330 m = 1.749 Nm
Net Torque = Torque1 + Torque2 = 2.475 Nm + 1.749 Nm = 4.224 Nm
Case 2: Forces F1 and F2 are applied in opposite rotational directions.
In this case, the net torque will be the difference between the individual torques due to F1 and F2.
Net Torque = Torque1 - Torque2 = 2.475 Nm - 1.749 Nm = 0.726 Nm
So, the net torque on the wheel depends on whether the forces are applied in the same rotational direction or not. If they are, the net torque is 4.224 Nm, and if they aren't, the net torque is 0.726 Nm.
Forces F1=7.50N and F2=5.30N are applied tangentially to a wheel with radius 0.330 m. What is the net torque on the wheel due to these two forces for an axis perpendicular to the wheel and passing through its center?
It depends upon whether or not the forces F1 and F2 are both in the same rotational direction. It they are, add the torques. If not, subtract one from the other. For a tangential force, torque = (force)x(radius)
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