To determine which of the equations shows work being calculated using the correct units, we should recall the formula for work (W):
\[ W = F \times d \]
Where:
- \( W \) is the work in joules (J)
- \( F \) is the force in newtons (N)
- \( d \) is the distance in meters (m)
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\( 113 N = (17.4 J) \times (6.51 ft) \)
- Incorrect: The units of the right side combine J (joules) and ft (feet), which is not consistent with force.
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\( 113 J = (17.4 N) \times (6.51 ft) \)
- Incorrect: The right side uses ft (feet), and we cannot calculate work in joules if distance is not in meters.
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\( 113 J = (17.4 N) \times (6.51 m) \)
- Correct: This equation properly uses force in newtons and distance in meters to calculate work in joules.
-
\( 113 N = (17.4 J) \times (6.51 m) \)
- Incorrect: The left side is not work but force, and the equation incorrectly pairs joules with meters.
The correct response is:
113 J = (17.4 N) × (6.51 m)
1 answer