for what whole number values of length and width will the rectangle have an area of 60 square yards and a perimeter of 38 yards?
2 answers
15 * 4
lw = 60 ---> l = 60/w
2l + 2w = 38 ---> l + w = 19
60/w + w = 19
times w
60 + w^2 = 19w
w^2 - 19w + 60 = 0
(w-15)(w-4) = 0
w = 15 or w = 4 , then
l = 4 or l = 15
the length is 15 and the width is 4
2l + 2w = 38 ---> l + w = 19
60/w + w = 19
times w
60 + w^2 = 19w
w^2 - 19w + 60 = 0
(w-15)(w-4) = 0
w = 15 or w = 4 , then
l = 4 or l = 15
the length is 15 and the width is 4
1 answer