For what values of y:

is the value of the fraction (7−2y)/6 greater than the value of the fraction (y−7)/12 ?

2 answers

(7−2y)/6 > (y−7)/12
2(7-2y) > y-7
14-4y > y-7
21 > 5y
21/5 > y
(7−2y)/6 > (y−7)/12

multiplying by 12 ... 14 - 4y > y - 7

adding 4y and 7 ... 21 > 5y
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