to have a parallogram, opposite sides must be equal, so
3a+1 = b, and 5a = 2b-5
use substitution ,
5a = 2(3a+1) - 5
solve for a, then you can find b in b = 3a+1
for what values of a and b is each quadrilateral a parallelogram?
Left side: 5a
Top: 3a+1
Right side: 2b-5
Bottom: b
1 answer