I think the problem is supposed to be this:
f(r)=r^2+5r+6/(r+2)
obviously, r cannot be -2.
Try -3. This problem is not rocket science. Plug in the values and compute
For what value(s) of r is r^2+5r+6/r+2 equal to 0?
A) -2 only
B) -3 only
C) 3 only
D)-2 or -3
E) 2 or 3
I got A but it is incorrect and I'm still confused
Thanks
4 answers
if r = -2, then the denominator is zero...a big no-no
factor the numerator and go with B
factor the numerator and go with B
maybe Scott is right, you meant
(r^2+5r+6)/(r+2 )
it is difficult to solve these if the function is not written with precision
(r^2+5r+6)/(r+2 )
it is difficult to solve these if the function is not written with precision
So the zero can only come from the numerator, thus
r^2 + 5r + 6 = 0
(r+2)(r+3) = 0
r = -2 or r = -3
BUT, as noted in your other replies, r cannot be -2
so r = -3
which is C
r^2 + 5r + 6 = 0
(r+2)(r+3) = 0
r = -2 or r = -3
BUT, as noted in your other replies, r cannot be -2
so r = -3
which is C