If 2x-3 is a factor of P(x)
then 2x-3 = 0
now solve this equation and draw your conclusion from the result
For what value of x should you evaluate the polynomial P(x)=2x^3−x^2−5x−2 to determine if 2x−3 is a factor of P(x)?
a. 3/2
b. 2/3
c.-3/2
d.-2/3
can someoone please help me with this im stumped and confused.
4 answers
Are you sure you write the question correctly?
2 x - 3 isn't a factor of 2x³ - x² - 5 x - 2
Factorisation:
2x³ - x² - 5 x - 2 = ( x + 1 ) ( 2 x + 1 ) ( x - 2 )
Long division:
( 2x³ - x² - 5 x - 2 ) / ( 2 x - 3 ) = x² + x - 1 - 5 / ( 2 x - 3 )
This division has a remainder of - 5 so 2 x - 3 isn't a factor.
2 x - 3 isn't a factor of 2x³ - x² - 5 x - 2
Factorisation:
2x³ - x² - 5 x - 2 = ( x + 1 ) ( 2 x + 1 ) ( x - 2 )
Long division:
( 2x³ - x² - 5 x - 2 ) / ( 2 x - 3 ) = x² + x - 1 - 5 / ( 2 x - 3 )
This division has a remainder of - 5 so 2 x - 3 isn't a factor.
so would that mean it would -3/2?
The question did not claim that P(x)=2x^3−x^2−5x−2 has a factor of 2x-3
It asked for the value of x one should try to see if 2x-3 is a factor, that would be 3/2
It asked for the value of x one should try to see if 2x-3 is a factor, that would be 3/2
1 answer