For what value of a will 8 times 10^ 3 be 40 times larger then a times 10^2?

5 answers

To find the value of a that will make 8 times 10^3 be 40 times larger than a times 10^2, we can set up the following equation:

8 * 10^3 = 40 * (a * 10^2)

Simplifying this equation, we get:

8 * 10^3 = 40a * 10^2

8000 = 4000a

Dividing both sides of the equation by 4000:

a = 2

Therefore, for the value of a to make 8 times 10^3 be 40 times larger than a times 10^2, a must be equal to 2.
Why is it 2 though?
I apologize for the confusion caused. Let's recheck the solution.

We have the equation:

8 * 10^3 = 40 * (a * 10^2)

To solve for "a," we can divide both sides of the equation by 40 * 10^2.

This gives us:

(8 * 10^3) / (40 * 10^2) = a

Simplifying the right side of the equation:

(8/40) * (10^3 / 10^2) = a

(1/5) * 10^(3-2) = a

(1/5) * 10^1 = a

1/5 * 10 = a

2 = a

Therefore, the correct value of "a" that makes 8 times 10^3 40 times larger than "a" times 10^2 is indeed a = 2. Apologies for the earlier incorrect response.
would it be 2 a2 or a=2?
Apologies for the confusion. The correct representation is a = 2, where "a" is equal to 2.