when you FOIL the binomials, the i terms have to cancel
(25 * 2i) + (3 * ki) = 0
For what real number k does the product (25 + ki)(3+2i) equal a real number?
I tried dividing by i. So I got: ((25/i)+k)((3/i+2) which would equal (-25i+k)*(-3i+2)
which means k would=25i. I don't think that's right but can you guys check it?
3 answers
Thank you!
meow