FOR WAT VALUE OF X IS THE TANGENT OF THE CURVE Y=X^2-4X+3 PARALLEL TO THE X AXIS

Answer 1

Note that the given equation is a parabola that opens upward. The only point on the graph where the tangent line is parallel to the x-axis is at the vertex of the parabola, where it is at minimum. The slope of the tangent line at this point is zero (y=0). To get this point, we get the derivative of y with respect to x:
y = x^2 - 4x + 3
0 = 2x - 4
x = 2 (answer)

if you want to get the point, we substitute this back to the original equation:
y = x^2 - 4x + 3
y = 2^2 - 4*2 + 3
y = -1
It occurs at (2, -1).

hope this helps~ :)

Answer 2

thanks u sweet