200cows * 2kwh/cow/day = 400kwh/day * 365 days/yr = 146000 kwh/yr
multiply by the value of a kwh to get the savings
Now figure the cost of running the digester for a year.
divide the cost by the savings to get the recovery time.
For Uncle Joe's dairy farm with 200 cows the cost of a methan digester is about 400 dollars. ASsume that the farm uses 800,000 kilowatt hours of electricity each year at a cost of $0.20 per kwh. The waste from a single cow can produce 2.0 kwh of electricity each day. Assuming the cost of electricity stays the same and Farmer Joe starts using manure from the cows in an aneorbic digester :
Calculate :
The number of KwH of electricity that can be produced in one year
The amount of money Farmer Joe will save in one year NOT counting the installation cost of the digester (round to nearest $1000)
The amount of time in years it will take to recover the cost of installing the digester on the farm (you may need to record your ansewr to nearest whole number)
3 answers
By how much does the mean of the data set below change if the outlier is removed round your answer to the nearest tenth if necassary
8,6,9,12,19,7,10,8
A. 0.5
B. 0.6
C. 1.3
D. 2.4
8,6,9,12,19,7,10,8
A. 0.5
B. 0.6
C. 1.3
D. 2.4
First, we need to find the mean of the entire data set:
Mean = (8+6+9+12+19+7+10+8)/8 = 9.875
Now, let's remove the outlier (19) and find the mean of the new data set:
Mean = (8+6+9+12+7+10+8)/7 = 8.57
The difference between the original mean and the new mean is:
9.875 - 8.57 = 1.305
Rounding to the nearest tenth, we get:
1.3
Therefore, the answer is C. 1.3.
Mean = (8+6+9+12+19+7+10+8)/8 = 9.875
Now, let's remove the outlier (19) and find the mean of the new data set:
Mean = (8+6+9+12+7+10+8)/7 = 8.57
The difference between the original mean and the new mean is:
9.875 - 8.57 = 1.305
Rounding to the nearest tenth, we get:
1.3
Therefore, the answer is C. 1.3.