For this equation
2 Ag+ (aq) + Cu(s) <--> Cu2+ (aq) + 2 Ag(s)
Which occurs at the anode?
A. Cu --> Cu2+ + 2e–
B. Cu2+ + 2e– --> Cu
C. Ag+ + e– -->Ag
D. Ag --> Ag+ + e–
A, right because it's oxidation?
3 answers
Oxidation occurs at the anode. Which is losing electrons.
So Cu--> Cu2+ +2e- is losing electrons, right? Because its becoming positive
That's right and the equation of Cu ==> Cu^2+ + 2e shows it losing two electrons.