E = 2.180E-19 x (1/9 - 1/16)
Then E = hc/wavelength
for the transition of an electron in a hydrogen atom between the principal quantum number levels 4 and 3, calculate
a) the energy released
b) the wavelength of the line in the spectra.
3 answers
can you explain it a little more cuz i really didn't understand anything!!!!
thank you!
thank you!
Energy in joules = 2.180E-19(1/n1^2 - 1/n2^2)
n1 = 3 and 1/n^2 is 1/9
n2 = 4 and 1/n^2 is 1/16
The rest of it is algebra.
After you have the energy, then set that in the following equation.
E = hc/wavelength.
h is Planck's constant in J.s
c is speed of light in m/s
wavelength is in meters. Plug and chug.
n1 = 3 and 1/n^2 is 1/9
n2 = 4 and 1/n^2 is 1/16
The rest of it is algebra.
After you have the energy, then set that in the following equation.
E = hc/wavelength.
h is Planck's constant in J.s
c is speed of light in m/s
wavelength is in meters. Plug and chug.