For the system CaO(s) + CO2(g) = CaCO3(s), I added 1.00 mol of CaO(s) to 1.00L of 0.500M CO2(g) at 200 oC. At equilibrium the [CO2] = 0.150M. What is the value of Kp for this reaction?

Question

For the system CaO(s) + CO2(g) = CaCO3(s),  I added 1.00 mol of CaO(s) to 1.00L of 0.500M CO2(g) at 200 oC.  At equilibrium the [CO2] = 0.150M.  What is the value of Kp for this reaction?

DrBob222 · Answer

..............CaO + CO2 ==> CaCO3 initial..... 1M...0.5M...... equil..............0.15 0.15M in 1L = 0.15 moles Use PV = nRT to solve for P, then Kp = 1/pCO2 = ?