[-b±√(b^2-4ac)]/2a
= [13±√(169+120)]/-12
= (13±√289)/-12
= (13±17)/-12
= 1/3 or -5/2
Did you take √ twice?
For the solution of finding zeros flr -6x^2-13x+5
When i use factoring and completing the squares the zeros are 1/3 and -5/2
However when i used the quadratic formula it gave me -13+ - sqrt of 17/ 12
Why is that. Is it still tge same
How
1 answer
1 answer