For the second part:

Question

The draw the plane vector which is the same as the desired results. At the end of the plane vector, draw the wind vector. That is where the plane will end up. So, for a 1/2 hour flight:
(80 km/h) * (hour/2) at 30 degrees E of S.
or 40km at 30 degrees E of S of the desired destination.

I don't understand the diagram. Can you please explain? I also don't understand why you used the wind velocity.

Answer 1

OK, here is what was stated for the continuation of the problem. I called this the second part.
"Suppose the pilot disregarded the wind and had flown in a direction of 30 degrees N of E. Where relative to his destination would he be when he thought he should be at the destination?"

Since the pilot is disregarding the wind, the plane would be flying at 30 degrees N of E. at 400km/h. But, since the wind is acting on the plane it will blow it off course. It would get to the destination OK if there was no wind.

Remember that the pilot is hoping to get to the destination which is 200km away in 0.5 hours.
First draw distance vector for the plane. It will be 200km at 30 N of E.
From the end of that vector (which actually ends at the hoped for destination) draw the distance due to the wind vector. That will be 40km (remember that this is a 1/2 hour trip). The wind drift will be in the same direction as the wind which will be 30 degrees E of S.

Answer 2

Thank you so much! I understand it now. With these problems I'm having a hard time deciphering the question.