For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants?

2Na(s)+Br2(g) ---->2NaBr(s)

1.
2mol Na, 2mol Br2

2.
1.8mol Na, 1.4mol Br2

3.
2.5mol Na, 1mol Br2

4.
12.6mol Na, 6.9 mol Br2

2 answers

#1.
2 mol Na needs 1/2 mol Br2. You have more than enough Br2 so the limiting reagent is Na.

#2.
1.8 mol Na needs 1.8 mols Na x (1 mol Br2/2 mols Na) = 1.8 x 1/2 = 0.9 mols Br2 and you have more than enough so the LR is Na.
okay but how bout the rest eh b'y