#1.
2 mol Na needs 1/2 mol Br2. You have more than enough Br2 so the limiting reagent is Na.
#2.
1.8 mol Na needs 1.8 mols Na x (1 mol Br2/2 mols Na) = 1.8 x 1/2 = 0.9 mols Br2 and you have more than enough so the LR is Na.
For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants?
2Na(s)+Br2(g) ---->2NaBr(s)
1.
2mol Na, 2mol Br2
2.
1.8mol Na, 1.4mol Br2
3.
2.5mol Na, 1mol Br2
4.
12.6mol Na, 6.9 mol Br2
2 answers
okay but how bout the rest eh b'y