mols KCl = M x L = ?
mols PbCl2 formed = ?mols KCl x (1 mol PbCl2/2 mols KCl) = ?mols KCl x 1/2 = ? mols PbCl2.
Then grams PbCl2 = mols PbCl2 x molar mass PbCl2.
For the reaction: Pb(NO3)2(aq) + 2KCl(aq)->PbCl2(s) + 2KNO3(aq)
How many grams of PbCl2 will be formed from 63.0 mL of a 1.60 M KCl solution?
1 answer
2 answers