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For the reaction I2 + Br2 <-> 2IBr Kc=280 at 150C . Suppose that 0.500 mol IBr in a 1.00-L flask is allowed to reach equilibrium at 150C.

What is the equilibrium concentration of IBr
What is the equilibrium concentration of I2
What is the equilibrium concentration of Br2

1 answer

(IBr) = 0.5 mol/K = 0.5M

...........I2 + Br2 ==> 2IBr
I..........0.....0.......0.5
C..........x.....x........-2x
E..........x.....x......0.5-2x

Write the Kc expression, substitute the E line, solve for x and evaluate 0.5-2x and x. Post your work if you get stuck.