For the reaction CO(g) + 2 H2(g) CH3OH(g) at 700. K, equilibrium concentrations are [H2] = 0.072 M, [CO] = 0.020 M, and [CH3OH] = 0.030 M.

Question

For the reaction CO(g) + 2 H2(g)  CH3OH(g) at 700. K, equilibrium concentrations are [H2] = 0.072 M, [CO] = 0.020 M, and [CH3OH] = 0.030 M.  
Calculate K.

What would K be?

DrBob222 · Answer

Tell me your problem with this so I'll know where to start. You need to learn to do these youself.

Doc48 · Answer

Kc = [CO][H₂]²/[CH₃OH] ... substitute given data and solve for Kc.

DrBob222 · Answer

oops. I have corrected the post by Doc. For the reaction CO(g) + 2 H2(g) ==> CH3OH(g) Kc =[CH₃OH]/[CO][H₂]²