NH3 + HCl ==> NH4Cl
mols NH4Cl = grams/molar mass = approx 12.5/53.5 = approx 0.23
Since 1 mol NH4Cl requires 1 mol NH3, plug 0.23 for mols into PV = nRT and solve for V in L.
For the reaction between ammonia and hydrochloric acid to produce ammonium chloride; What volume of ammonia is used (at 20 Celsius and 760mmHg) if 12.5gmof ammonium chloride are produced in the reaction? How many molecules of ammonia does this represent?
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