Just another Kc problem.
......................Pb(s) + 2 Cr3+(aq) ⇌ Pb2+(aq) + 2 Cr2+(aq)
I.....................solid........1M..................0...................0
C....................solid.......-2x...................x...................2x
E.....................solid.......1-2x.................x....................2x
Plug the E line into the Kc expression and solve for x, then evaluate the individual items in the E line. Post your work if you get stuck.
For the reaction below, the equilibrium constant is Kc = 3.2×10−10 at 25 °C.
Pb(s) + 2 Cr3+(aq) ⇌ Pb2+(aq) + 2 Cr2+(aq)
Excess Pb(s) is added to a solution for which the initial concentration of Cr3+(aq) is 1.0 mol L−1. What are the equilibrium concentrations of Pb2+ and Cr2+ ?
3 answers
how do i determine the Kc expression?
i got: 3.2×10−10 = 2x^2(x) / (1-2x^2)... does that look right so far
1 answer