Thomas, it wouldn't hurt to read over your posts before you push that submit button. No caps and no periods and typos to boot leave a post that's difficult to interpret. For this one I've guessed at half of the question; assuming I've guessed right you do the problem this way.
dG = dH - TdS
At the spontaneous stage, dG must be negative so substitute zero, the tipping point, for dG.
That gives you TdS = dH. Substitute the values for dS and dH and solve for T.
for the reaction at 298 K 2A+b ---->C
enthalpy=100 K/cal entropy= 0.050 kcal/k
assuming enthalpy and entropy to be constant over the temperature range, at what temperature will the reaction become spontaneous?
answer: T>2000K
2 answers
thanks