Asked by Samuel
For the rational equation 6x+5/x^2+2x+2=6x-7/x^2-2x+2, do each of the following:
a. using successive approximations, find an approximate solution on the interval [-2,-1] such that the difference between the two sides of the equation is less than 0.1. your answer should be the midpoint of an interval.
b. state the interval for which the solution is a midpoint
c. show that the difference of the two sides of the equation is less than 0.1 for this value of x.
a. using successive approximations, find an approximate solution on the interval [-2,-1] such that the difference between the two sides of the equation is less than 0.1. your answer should be the midpoint of an interval.
b. state the interval for which the solution is a midpoint
c. show that the difference of the two sides of the equation is less than 0.1 for this value of x.
Answers
Answered by
oobleck
you want the difference to be small, so start checking
(6x+5)/(x^2+2x+2) - (6x-7)/(x^2-2x+2)
y = -4(3x^2-x-6)/(x^4+1)
Since the denominator is always positive, you want to find an interval containing a zero of
f(x) = 3x^2-x-6
f(-2) = 14
f(-1) = -2
So now find y(1.5) and keep subdividing the interval till you get |y| < 0.1
(6x+5)/(x^2+2x+2) - (6x-7)/(x^2-2x+2)
y = -4(3x^2-x-6)/(x^4+1)
Since the denominator is always positive, you want to find an interval containing a zero of
f(x) = 3x^2-x-6
f(-2) = 14
f(-1) = -2
So now find y(1.5) and keep subdividing the interval till you get |y| < 0.1
Answered by
Samuel
Thank you so much for the help!
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