x of the vertex is -b/(2a) -----> good formula to memorize
= -(-16)/(4) = 4
f(4) = ....
so now you have the vertex.
easy to read off the max/min and the axis of symmetry.
for x intercept let y = 0 in y = 2x^2 - 16x + 27
for y intercept let x = 0 in y = 2x^2 - 16x + 27
confirm my looking at the graph:
http://www.wolframalpha.com/input/?i=y+%3D+2x%5E2+-+16x+%2B+27
For the quadratic function f(x) = 2x^2 - 16x + 27
The Vertex = ___?
f(x) attains a maximum minimum value of ___?
The axis of symmetry is___?
The x-intercepts are___? and The y-intercept is ____?
1 answer
1 answer