To solve the quadratic equation \((x-7)^2=11\), we can start by taking the square root of both sides:
\[ x - 7 = \pm \sqrt{11} \]
Then, we can solve for \(x\):
-
\(x - 7 = \sqrt{11}\) \[ x = 7 + \sqrt{11} \]
-
\(x - 7 = -\sqrt{11}\) \[ x = 7 - \sqrt{11} \]
Now we have the two solutions:
- The smaller solution is \(x = 7 - \sqrt{11}\).
- The larger solution is \(x = 7 + \sqrt{11}\).
To get numerical approximations for the roots:
- \(\sqrt{11} \approx 3.32\)
- Therefore:
- The smaller solution is approximately \(7 - 3.32 \approx 3.68\).
- The larger solution is approximately \(7 + 3.32 \approx 10.32\).
Thus, the two solutions to the quadratic equation are:
- The smaller of the two solutions is \(x \approx 3.68\) or the exact form \(x = 7 - \sqrt{11}\).
- The larger of the two solutions is \(x \approx 10.32\) or the exact form \(x = 7 + \sqrt{11}\).
Answer:
The smaller solution is \(x = 7 - \sqrt{11}\).
The larger solution is \(x = 7 + \sqrt{11}\).