To determine if the given values are solutions to the quadratic equation \(5x^2 + 16x - 16 = 0\), we will substitute each value into the equation and check if the equation equals zero.
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Testing \(x = 0\): \[ 5(0)^2 + 16(0) - 16 = 0 + 0 - 16 = -16 \quad (\text{Is not a solution}) \]
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Testing \(x = -4\): \[ 5(-4)^2 + 16(-4) - 16 = 5(16) - 64 - 16 = 80 - 64 - 16 = 0 \quad (\text{Is a solution}) \]
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Testing \(x = 4\): \[ 5(4)^2 + 16(4) - 16 = 5(16) + 64 - 16 = 80 + 64 - 16 = 128 \quad (\text{Is not a solution}) \]
Now, we can summarize the results in the table:
- For 0: Is not a solution
- For -4: Is a solution
- For 4: Is not a solution
Final Responses:
- 0: Is not a solution
- -4: Is a solution
- 4: Is not a solution