For the picture below FG ¯¯¯¯¯¯¯¯¯

Question

is a perpendicular bisector of AB¯¯¯¯¯¯¯¯
. Which points are equidistant from points A and B? Check ALL that apply

(4 points)
Responses

W
W - no response given

X
X - no response given

Y
Y - correct

Z
Z - correct

P
P - no response given

S
S - no response given

F
F - correct

G
G - correct
Question 4
Which theorem proves this?(1 point)
Responses

Vertical Angles theorem
Vertical Angles theorem

Converse of Alternate Interior Angles Theorem
Converse of Alternate Interior Angles Theorem

Perpendicular Bisector Theorem
Perpendicular Bisector Theorem

Triangle Sum Theorem
Triangle Sum Theorem

Answer 1

To answer your first question, the points that are equidistant from points \( A \) and \( B \) are indeed those that lie on the perpendicular bisector \( FG \) of segment \( AB \). Based on your notation, the following points are correct:

• Y - correct
• Z - correct
• F - correct
• G - correct

Since you also have points W, X, P, and S with "no response given", it appears that they may not be relevant or correct in this context.

As for your second question regarding the theorem that proves which points are equidistant from \( A \) and \( B \), the correct response is:

• Perpendicular Bisector Theorem

This theorem states that any point on the perpendicular bisector of a line segment is equidistant from the endpoints of that segment.