For the intergral of -(x^2)/3 +6 interval [0,3]
Rewrite it as a function of n using the right hand endpoint without any summation sign.
can anyone help me start this problem out?
I noticed somebody else had that post before, perhaps it was you.
I am not sure exactly what you are asking, I am not familiar with the terminology you are using.
do you want the integral of -1/3(x^2) + 6 from 0 to 3?
the integral would be -1/9(x^3) + 6x + c
which when evaluated is 15
i know how to evaluate the equation but how do i rewrite it as a function of n using the right hand endpoint.
i got delta x =3/n and x*k=3k/n
what do i do next?