The series can be represented in sigma notation as follows:
∑ (162/3^(n-1)) from n = 1 to ∞
For the infinite series 162 + 54 + 18 + 6 + …
what is it in sigma notation where n = 1?
3 answers
or,
∞
∑ 162/3^n
n=0
∞
∑ 162/3^n
n=0
Yes, you can also represent the series as:
∑ (162/3^n) from n = 0 to ∞
∑ (162/3^n) from n = 0 to ∞