For the given equation, find the slope of the tangent to the curve at the point (-4,2).

Question

y^2+8y+x^2+8x-4=0

A. -1.50
B. -0.50
C. -2.00
D. 0.00
E. UNDEFINED

Answer 1

2yy'+8y'+2x+8=0

y'= (-2x-8)/(2y+8) check that.

y'=0

Answer 2

Is it undefined or just 0.00?

Answer 3

Is it 0/0? that is undefined. If it is 0/realnumber, it is zero.

Answer 4

ok, thanks.