For the functions f(x)=x-4 and g(x)=2x^2-3x-1, Find:

Question

A. (f*g)(x)
B. (f*g)(-1)

Answer 1

(f*g)(x) = f(x)*g(x) = (x-4)(2x^2-3x-1)
so,
(f*g)(-1) = (-1-4)(2(-1)^2-3(-1)-1)
= (-5)(2+3-1)
= -20