Asked by d
For the function f(x)=8x−9
, find f−1(x)
.(1 point)
Responses
f−1(x)=(x−9)8
f inverse of x is equal to the fraction with numerator open paren x minus 9 close paren and denominator 8
f−1(x)=x8+9
f inverse of x is equal to x over 8 plus 9
f−1(x)=8x+9
f inverse of x is equal to 8 x plus 9
f−1(x)=(x+9)8
f inverse of x is equal to the fraction with numerator open paren x plus 9 close paren and denominator 8
, find f−1(x)
.(1 point)
Responses
f−1(x)=(x−9)8
f inverse of x is equal to the fraction with numerator open paren x minus 9 close paren and denominator 8
f−1(x)=x8+9
f inverse of x is equal to x over 8 plus 9
f−1(x)=8x+9
f inverse of x is equal to 8 x plus 9
f−1(x)=(x+9)8
f inverse of x is equal to the fraction with numerator open paren x plus 9 close paren and denominator 8
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the inverse of the function \( f(x) = 8x - 9 \), we follow these steps:
1. **Replace \( f(x) \) with \( y \)**:
\[
y = 8x - 9
\]
2. **Swap \( x \) and \( y \)**:
\[
x = 8y - 9
\]
3. **Solve for \( y \)**:
\[
x + 9 = 8y
\]
\[
y = \frac{x + 9}{8}
\]
So, the inverse function is:
\[
f^{-1}(x) = \frac{x + 9}{8}
\]
Now, let's match it with the given responses:
The correct option is:
- **f−1(x) is equal to the fraction with numerator (x + 9) and denominator 8.**
1. **Replace \( f(x) \) with \( y \)**:
\[
y = 8x - 9
\]
2. **Swap \( x \) and \( y \)**:
\[
x = 8y - 9
\]
3. **Solve for \( y \)**:
\[
x + 9 = 8y
\]
\[
y = \frac{x + 9}{8}
\]
So, the inverse function is:
\[
f^{-1}(x) = \frac{x + 9}{8}
\]
Now, let's match it with the given responses:
The correct option is:
- **f−1(x) is equal to the fraction with numerator (x + 9) and denominator 8.**
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