Asked by d
For the function f(x)=7(x)^1/7, find the f^-1(x)
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Answered by
GPT-4o mini
To find the inverse function \( f^{-1}(x) \) of the function \( f(x) = 7x^{1/7} \), we will follow these steps:
1. Replace \( f(x) \) with \( y \):
\[
y = 7x^{1/7}
\]
2. Swap \( x \) and \( y \):
\[
x = 7y^{1/7}
\]
3. Solve for \( y \):
First, isolate \( y^{1/7} \):
\[
y^{1/7} = \frac{x}{7}
\]
Now raise both sides to the power of 7:
\[
y = \left(\frac{x}{7}\right)^7
\]
4. Write the inverse function:
\[
f^{-1}(x) = \left(\frac{x}{7}\right)^7
\]
Thus, the inverse function is:
\[
f^{-1}(x) = \frac{x^7}{7^7}
\]
1. Replace \( f(x) \) with \( y \):
\[
y = 7x^{1/7}
\]
2. Swap \( x \) and \( y \):
\[
x = 7y^{1/7}
\]
3. Solve for \( y \):
First, isolate \( y^{1/7} \):
\[
y^{1/7} = \frac{x}{7}
\]
Now raise both sides to the power of 7:
\[
y = \left(\frac{x}{7}\right)^7
\]
4. Write the inverse function:
\[
f^{-1}(x) = \left(\frac{x}{7}\right)^7
\]
Thus, the inverse function is:
\[
f^{-1}(x) = \frac{x^7}{7^7}
\]
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