To find the inverse function \( f^{-1}(x) \) of the given function \( f(x) = 4x + 2 \), we will follow these steps:
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Replace \( f(x) \) with \( y \): \[ y = 4x + 2 \]
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Swap \( x \) and \( y \): \[ x = 4y + 2 \]
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Solve for \( y \): \[ x - 2 = 4y \] \[ y = \frac{x - 2}{4} \]
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Replace \( y \) with \( f^{-1}(x) \): \[ f^{-1}(x) = \frac{x - 2}{4} \]
Thus, the inverse function is: \[ f^{-1}(x) = \frac{x - 2}{4} \]