For the function F(t)=3^t, let f(t)=F′(t). Write the integral ∫^{b}_a f(t)dt and evaluate it with the Fundamental Theorem of Calculus.
∫^{3}_0 =
dt=
(Note that your answer must be exact, not a decimal approximation.)
1 answer
∫[a,b] f(t) dt = F(b) - F(a) = 3^b - 3^a