without tipping the see-saw assuming the distance from the pivot point to the load is 2 meters and the distance from the pivot point to the person pushing down on the other end is 1 meter and the person pushing down has a weight of 80 kg.
To calculate the load that could be lifted without tipping the see-saw, we need to use the principle of moments: the sum of the moments on either side of the pivot point must be equal for the see-saw to be in balance.
Let L be the load that could be lifted, and W be the weight of the person pushing down. The moments are:
- For the load: L × 2
- For the person: W × 1
Since the see-saw is in balance, these moments must be equal:
L × 2 = W × 1
We can solve for L:
L = W/2
Plugging in W = 80 kg, we get:
L = 80/2 = 40 kg
So the load that could be lifted without tipping the see-saw is 40 kg.
For the following simple see-saw calculate
1 the load that could be lifted
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