For the following simple see-saw calculate

1 the load that could be lifted

1 answer

without tipping the see-saw assuming the distance from the pivot point to the load is 2 meters and the distance from the pivot point to the person pushing down on the other end is 1 meter and the person pushing down has a weight of 80 kg.

To calculate the load that could be lifted without tipping the see-saw, we need to use the principle of moments: the sum of the moments on either side of the pivot point must be equal for the see-saw to be in balance.

Let L be the load that could be lifted, and W be the weight of the person pushing down. The moments are:

- For the load: L × 2
- For the person: W × 1

Since the see-saw is in balance, these moments must be equal:

L × 2 = W × 1

We can solve for L:

L = W/2

Plugging in W = 80 kg, we get:

L = 80/2 = 40 kg

So the load that could be lifted without tipping the see-saw is 40 kg.