For the following redox reaction, identify the oxidizing agent and the reducing agent.

Cu(NO3)2 (aq) + Mg(s) ® Cu(s) + Mg(NO3)2 (aq

4 answers

1. Go through and assign oxidation numbers to each element.
2. Mark those that have changed.
3. Determine the ones that lost/gained electrons.
4. The oxidizing agent gains electrons; the reducing agent loses electrons.

Post your work or explain in detail what you don't understand.
My problem is the CU(NO3)2 and Mg(NO3)2
Mg alone is 0 and Cu alone is 0
Ok i think i got it, Cu in the compound is +2 and Mg in the compound is +2
So Cu is the OD and Mg is the RA
Yes, you have it. Good work.
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