1. Go through and assign oxidation numbers to each element.
2. Mark those that have changed.
3. Determine the ones that lost/gained electrons.
4. The oxidizing agent gains electrons; the reducing agent loses electrons.
Post your work or explain in detail what you don't understand.
For the following redox reaction, identify the oxidizing agent and the reducing agent.
Cu(NO3)2 (aq) + Mg(s) ® Cu(s) + Mg(NO3)2 (aq
4 answers
My problem is the CU(NO3)2 and Mg(NO3)2
Mg alone is 0 and Cu alone is 0
Mg alone is 0 and Cu alone is 0
Ok i think i got it, Cu in the compound is +2 and Mg in the compound is +2
So Cu is the OD and Mg is the RA
So Cu is the OD and Mg is the RA
Yes, you have it. Good work.