For the following reaction, what is the approximate value of Delta H?
CH4(g) --> CH3(g) + H(g)
I figured it out..
C-H = 411
4 moles on one side
3 on the other
so [4*411]-[3*411] = 411
CH4(g) --> CH3(g) + H(g)
I figured it out..
C-H = 411
4 moles on one side
3 on the other
so [4*411]-[3*411] = 411