S + 2CO ==> SO2 + 2C
mols S = grams/molar mass = ?
mols CO = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols S to mols SO2.
Do the same for mols CO to mols SO2.
It is likely that these two values for mols SO2 will not agree which means one is not right; the correct value in limiting (LR) reactions is always the smaller value and the reagent responsible for this is the LR (that will give you the formula for the LR). Then grams SO2 = mols SO2 x molar mass SO2.
For the excess reagent, use the coefficients in the balanced equation to convert mols LR to the excess reagent used up, then subtract initial amount of excess reagent - amount used up, and convert that to grams. Post your work if you get stuck.
For the following reaction, 9.91 grams of sulfur are allowed to react with 20.8 grams of carbon monoxide .
sulfur(s) + carbon monoxide(g) sulfur dioxide(g) + carbon(s)
is the maximum amount of sulfur dioxide that can be formed?
What is the FORMULA for the limiting reagent?
What amount of the excess reagent remains after the reaction is complete?
1 answer
1 answer