For the following question, assume that lines that appear to be tangent are tangent. Point O is the center of the circle. Find the value of x. Figures are not drawn to scale.

Question

m angle Upper P equals 16°
Center point O of a circle forms the vertex of triangle POQ. The angle at point O is labeled x degrees. Side QO is the radius of the circle.
(1 point)
Responses

74
74

32
32

106
106

37

Answer 1

To find the value of x, we can use the fact that the angles in a triangle add up to 180 degrees. Since we know that angle P = 16 degrees, we can find angle Q by subtracting 16 from 180: 180 - 16 = 164 degrees.

In triangle POQ, the angles at P, O, and Q add up to 180 degrees. So, we can set up the equation:

16 + x + 164 = 180

Combine like terms:

x + 180 = 180

Subtract 180 from both sides:

x = 0

Therefore, the value of x is 0 degrees.