Sorry, I forgot to post the function:
f(x)=cos3x
For the following function, find the relative max's or min's using any method.
I'm having a hard time finding the critical points...
2 answers
surely you jest! The critical points are where f' = 0.
f'(x) = -3sin3x
You know that sin(u)=0 when u is a multiple of pi.
So, f'(x) = 0 when 3x is a multiple of pi:
x= 0, pi/3, 2pi/3, ...
f'(x) = -3sin3x
You know that sin(u)=0 when u is a multiple of pi.
So, f'(x) = 0 when 3x is a multiple of pi:
x= 0, pi/3, 2pi/3, ...