For the following function find f(-2.9) and f(0)
f(x)={(2x+7, -5<=x<-3),(-(3)/(4)(x+2)^(2)+3, -3<=x<0),(2\log _(5)(x+1)-2, 0<=x<4)}
Answer choices:
f(-2.9)= 1.2 and f(0)= 0
f(-2.9)= 1.2 and f(0)= -2
f(-2.9)= 2.3925 and f(0)= 0
f(-2.9)= 2.3925 and f(0)= -2
Im thinkin its B but I really just guessed I dont know whats going on
2 answers
use symbolab
although this is old, for anyone struggling i will explain it and give the answer because i struggled a bit too until i watched a video on it!
to find f(-2.9) you're going to have to find where -2.9 lies in the inequalities.
we have -5<=x<3, -3<=x<0, and 0<=x<4. -2.9 lies in -3<=x<0 and the function matching with those inequalities is f(x)= -3/4(x+2)^2+3. plug in -2.9 for x and you will get f(-2.9)= 2.3925.
do the same with 0. the function you will plug in 0 to is f(x)= 2log_5(x+1)-2. you will get f(0)= -2.
so TL;DR, f(-2.9)= 2.3925 and f(0)= -2
hope this helps!!<3
to find f(-2.9) you're going to have to find where -2.9 lies in the inequalities.
we have -5<=x<3, -3<=x<0, and 0<=x<4. -2.9 lies in -3<=x<0 and the function matching with those inequalities is f(x)= -3/4(x+2)^2+3. plug in -2.9 for x and you will get f(-2.9)= 2.3925.
do the same with 0. the function you will plug in 0 to is f(x)= 2log_5(x+1)-2. you will get f(0)= -2.
so TL;DR, f(-2.9)= 2.3925 and f(0)= -2
hope this helps!!<3