20X^2 - 5X + 3 = 0.
D = B^2 - 4AC = 25 - 240 = -215.
The discriminant is negative.Therefore we have 2 imaginary solutions,and no
real solutions.
for the following equation, state the value of the discriminate and then describe the nature of the solutions, from the following statements. -20x^2-5x+3=0
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