d = b^2 - 4ac = 64 - 4(-3)(-11) = 64-132 = -68
since d < 0, there are two complex solutions
For the following equation, state the value of the discriminant and then the nature of the soluation:
-3x^2-8x-11=0
Is there one real solution, two imaginary solutions or two real solutions?
1 answer