1) both removing some iodine gas and removing some HI(g)
2) decreasing temperature
3) removing some iodine gas
4) removing some HI(g)
5) removing some HI(g) & decreasing temperature
For the equilibrium system below, which of the following would result in an increase in the quantity of H2(g)?
H2(g) + I2(g) <——-> 2Hl(g) + 65 kJ
2 answers
If we disturb a system in equilibrium the reaction will shift (move left or right) so as to undo what we do to it.
Therefore, removing H2 will move it to the left thus increasing I2 and decreasing HI. Removing I2 moves it to the left also.
Removing HI moves it to the right, thus increasing HI and decreasing H2 and I2.
Does that look like 3 for the answer.
Adding heat moves it to the left; decreasing T moves it to the right.
Therefore, removing H2 will move it to the left thus increasing I2 and decreasing HI. Removing I2 moves it to the left also.
Removing HI moves it to the right, thus increasing HI and decreasing H2 and I2.
Does that look like 3 for the answer.
Adding heat moves it to the left; decreasing T moves it to the right.
2 answers